What is the solution for y^'=((6t^2))/y ?

The solution for y^'=((6t^2))/y is y=sqrt(4t^3+c_{1)},y=-sqrt(4t^3+c_{1)}

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y^'=((6t^2))/y

y^{^{'}} = \frac{( 6 t ^{2} )}{y}

y = 4 t^{3} + c_{1}, y = - 4 t^{3} + c_{1}

Solution steps

y^{'} (t) = \frac{( 6 t ^{2} )}{y}

Solve separable ODE:

y = 4 t^{3} + c_{1}, y = - 4 t^{3} + c_{1}

y = 4 t^{3} + c_{1}, y = - 4 t^{3} + c_{1}

x \to a lim (- 6)

- 0.5 cos (8 t)

\frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} + y = \frac{e ^{x}}{x ^{2} + 1}

\frac{d}{d x} ((x)^{\frac{3}{2}})

y^{^{''}} - 7 y^{^{'}} + 6 y = - 4 e^{- 5 t}

What is the solution for y^'=((6t^2))/y ?
The solution for y^'=((6t^2))/y is y=sqrt(4t^3+c_{1)},y=-sqrt(4t^3+c_{1)}