What is the derivative of-0.5cos(8t) ?

The derivative of-0.5cos(8t) is 4sin(8t)

What is the first derivative of-0.5cos(8t) ?

The first derivative of-0.5cos(8t) is 4sin(8t)

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derivative of

- 0.5 cos (8 t)

4 sin (8 t)

Solution steps

\frac{d}{d t} (- 0.5 cos (8 t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 0.5 \frac{d}{d t} (cos (8 t))

Apply the chain rule:

- sin (8 t) \frac{d}{d t} (8 t)

= - sin (8 t) \frac{d}{d t} (8 t)

\frac{d}{d t} (8 t) = 8

= - 0.5 (- sin (8 t) \cdot 8)

Simplify

= 4 sin (8 t)

\frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} + y = \frac{e ^{x}}{x ^{2} + 1}

\frac{d}{d x} ((x)^{\frac{3}{2}})

y^{^{''}} - 7 y^{^{'}} + 6 y = - 4 e^{- 5 t}

\frac{∣ x ∣}{2 - x ^{2}}

\frac{d y}{d x} = \frac{( y ^{2} )}{2 x + 3}

What is the derivative of-0.5cos(8t) ?
The derivative of-0.5cos(8t) is 4sin(8t)
What is the first derivative of-0.5cos(8t) ?
The first derivative of-0.5cos(8t) is 4sin(8t)