What is the solution for (dy)/(dx)=((y^2))/(2x+3) ?

The solution for (dy)/(dx)=((y^2))/(2x+3) is y=-2/(ln(3+2x)+c_{1)}

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(dy)/(dx)=((y^2))/(2x+3)

\frac{d y}{d x} = \frac{( y ^{2} )}{2 x + 3}

y = - \frac{2}{ln ( 3 + 2 x ) + c _{1}}

Solution steps

\frac{d y}{d x} = \frac{( y ^{2} )}{2 x + 3}

Solve separable ODE:

y = - \frac{2}{ln ( 3 + 2 x ) + c _{1}}

y = - \frac{2}{ln ( 3 + 2 x ) + c _{1}}

\int (\frac{x + 2}{x}) d x

f (x) = 3 x + 4, at x = 7

\int_{3}^{4} \frac{1}{( x - 3 ) ^{3}} d x

f (x) = 3 x^{- 2}, at x = 4

x \to + 0 lim (1 + sinh (2 x))

What is the solution for (dy)/(dx)=((y^2))/(2x+3) ?
The solution for (dy)/(dx)=((y^2))/(2x+3) is y=-2/(ln(3+2x)+c_{1)}