What is the tangent of f(x)=sqrt(3x+4),\at x=7 ?

The tangent of f(x)=sqrt(3x+4),\at x=7 is y= 3/10 x+29/10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=sqrt(3x+4),\at x=7

tangent of

f (x) = 3 x + 4, at x = 7

y = \frac{3}{10} x + \frac{29}{10}

Solution steps

Find the tangent point:

(7, 5)

Find the slope of

f (x) = 3 x + 4 : \frac{df ( x )}{d x} = \frac{3}{2 3 x + 4}

Compute the slope of

f (x) = 3 x + 4

x = 7 : m = \frac{3}{10}

Find the line with slope m=

\frac{3}{10}

and passing through

(7, 5) : y = \frac{3}{10} x + \frac{29}{10}

y = \frac{3}{10} x + \frac{29}{10}

\int_{3}^{4} \frac{1}{( x - 3 ) ^{3}} d x

f (x) = 3 x^{- 2}, at x = 4

x \to + 0 lim (1 + sinh (2 x))

\frac{d y}{d x} = \frac{6 x}{5 y}

\int_{0}^{π^{2}} sin (x) d x

What is the tangent of f(x)=sqrt(3x+4),\at x=7 ?
The tangent of f(x)=sqrt(3x+4),\at x=7 is y= 3/10 x+29/10