What is the integral of xsec(x^2) ?

The integral of xsec(x^2) is 1/2 ln|tan(x^2)+sec(x^2)|+C

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integral of xsec(x^2)

\int x sec (x^{2}) d x

\frac{1}{2} ln tan (x^{2}) + sec (x^{2}) + C

Solution steps

\int x sec (x^{2}) d x

Apply u-substitution

: \int \frac{sec ( u )}{2} d u

= \int \frac{sec ( u )}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int sec (u) d u

Use the common integral:

\int sec (u) d u = ln ∣ tan (u) + sec (u) ∣

= \frac{1}{2} ln ∣ tan (u) + sec (u) ∣

Substitute back

u = x^{2}

= \frac{1}{2} ln tan (x^{2}) + sec (x^{2})

Add a constant to the solution

= \frac{1}{2} ln tan (x^{2}) + sec (x^{2}) + C

y = 16 x, (4, 32)

\int \frac{( x - 3 ) ^{3}}{x ^{2} - 9} d x

\int \frac{x sin ( x )}{cos ^{2} ( x )} d x

\frac{\partial}{\partial x} (x yz ln (x + y))

x \to 4 - lim (8 - 2 x)

What is the integral of xsec(x^2) ?
The integral of xsec(x^2) is 1/2 ln|tan(x^2)+sec(x^2)|+C