What is the derivative of 3sqrt(x)-6\sqrt[3]{x} ?

The derivative of 3sqrt(x)-6\sqrt[3]{x} is 3/(2sqrt(x))-2/(x^{2/3)}

What is the first derivative of 3sqrt(x)-6\sqrt[3]{x} ?

The first derivative of 3sqrt(x)-6\sqrt[3]{x} is 3/(2sqrt(x))-2/(x^{2/3)}

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\frac{3}{2 x} - \frac{2}{x ^{\frac{2}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (3 x) = \frac{3}{2 x}

= \frac{3}{2 x} - \frac{2}{x ^{\frac{2}{3}}}

n = 1 \sum \infty n^{(- \frac{2}{3})}

\frac{d}{d x} ((x + 2)^{- 1})

x - 2

x \to - 5 lim (x^{2})

n = 1.0 E 22 \sum \infty \frac{1}{n}

What is the derivative of 3sqrt(x)-6\sqrt[3]{x} ?
The derivative of 3sqrt(x)-6\sqrt[3]{x} is 3/(2sqrt(x))-2/(x^{2/3)}
What is the first derivative of 3sqrt(x)-6\sqrt[3]{x} ?
The first derivative of 3sqrt(x)-6\sqrt[3]{x} is 3/(2sqrt(x))-2/(x^{2/3)}