What is the derivative of (x+2^{-1}) ?

The derivative of (x+2^{-1}) is -1/((x+2)^2)

What is the first derivative of (x+2^{-1}) ?

The first derivative of (x+2^{-1}) is -1/((x+2)^2)

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\frac{d}{d x} ((x + 2)^{- 1})

- \frac{1}{( x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} ((x + 2)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 2 ) ^{2}} \frac{d}{d x} (x + 2)

= - \frac{1}{( x + 2 ) ^{2}} \frac{d}{d x} (x + 2)

\frac{d}{d x} (x + 2) = 1

= - \frac{1}{( x + 2 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( x + 2 ) ^{2}}

x - 2

x \to - 5 lim (x^{2})

n = 1.0 E 22 \sum \infty \frac{1}{n}

\int_{0}^{1} (3 x + 1)^{2} d x

f (x) = 8 x + 1

What is the derivative of (x+2^{-1}) ?
The derivative of (x+2^{-1}) is -1/((x+2)^2)
What is the first derivative of (x+2^{-1}) ?
The first derivative of (x+2^{-1}) is -1/((x+2)^2)