What is the derivative of f(x)=sqrt(8x+1) ?

The derivative of f(x)=sqrt(8x+1) is 4/(sqrt(8x+1))

What is the first derivative of f(x)=sqrt(8x+1) ?

The first derivative of f(x)=sqrt(8x+1) is 4/(sqrt(8x+1))

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derivative of

f (x) = 8 x + 1

\frac{4}{8 x + 1}

Solution steps

\frac{d}{d x} (8 x + 1)

Apply the chain rule:

\frac{1}{2 8 x + 1} \frac{d}{d x} (8 x + 1)

= \frac{1}{2 8 x + 1} \frac{d}{d x} (8 x + 1)

\frac{d}{d x} (8 x + 1) = 8

= \frac{1}{2 8 x + 1} \cdot 8

Simplify

\frac{1}{2 8 x + 1} \cdot 8 : \frac{4}{8 x + 1}

= \frac{4}{8 x + 1}

\frac{7 s + 10}{7 s ^{2} + 26 s + 25}

f (x) = - tan (x)

y = e^{4 x^{2}}

\int_{- 2}^{3} \frac{30}{x ^{4}} d x

\int - \frac{y}{z ^{2}} d z

What is the derivative of f(x)=sqrt(8x+1) ?
The derivative of f(x)=sqrt(8x+1) is 4/(sqrt(8x+1))
What is the first derivative of f(x)=sqrt(8x+1) ?
The first derivative of f(x)=sqrt(8x+1) is 4/(sqrt(8x+1))