What is the derivative of y= x/(2x-4) ?

The derivative of y= x/(2x-4) is -1/((x-2)^2)

What is the first derivative of y= x/(2x-4) ?

The first derivative of y= x/(2x-4) is -1/((x-2)^2)

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derivative of

y = \frac{x}{2 x - 4}

- \frac{1}{( x - 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{2 x - 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d x}{d x} ( 2 x - 4 ) - \frac{d}{d x} ( 2 x - 4 ) x}{( 2 x - 4 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (2 x - 4) = 2

= \frac{1 \cdot ( 2 x - 4 ) - 2 x}{( 2 x - 4 ) ^{2}}

Simplify

\frac{1 \cdot ( 2 x - 4 ) - 2 x}{( 2 x - 4 ) ^{2}} : - \frac{1}{( x - 2 ) ^{2}}

= - \frac{1}{( x - 2 ) ^{2}}

\frac{d}{d x} (\frac{r ( x )}{x})

f (x) = e^{x}

y = 6 x^{2} + 3 x - 9

\int e^{- 2 u} d u

\int_{1}^{3} (3 x + 2)^{2} d x

What is the derivative of y= x/(2x-4) ?
The derivative of y= x/(2x-4) is -1/((x-2)^2)
What is the first derivative of y= x/(2x-4) ?
The first derivative of y= x/(2x-4) is -1/((x-2)^2)