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Popular >

y^'=5-2y

Solution

y^{^{'}} = 5 - 2 y

Solution

y = - \frac{e ^{- 2 t - c_{1}}}{2} + \frac{5}{2}

Solution steps

y^{'} (t) = 5 - 2 y

Solve separable ODE:

y = - \frac{e ^{- 2 t - c_{1}}}{2} + \frac{5}{2}

y = - \frac{e ^{- 2 t - c_{1}}}{2} + \frac{5}{2}

Popular Examples

y^{^{'}} = cos^{2} (y)

tangent of y=(x^2)/(x+1),(2, 4/3)tangent of

y = \frac{x ^{2}}{x + 1}, (2, \frac{4}{3})

(dy)/(dx)+6xy^5=0

\frac{d y}{d x} + 6 x y^{5} = 0

(7x+11y)dx+(11x+5y)dy=0,y(0)=2

(7 x + 11 y) d x + (11 x + 5 y) d y = 0, y (0) = 2

(\partial)/(\partial x)(y/(2sqrt(x))-4)

\frac{\partial}{\partial x} (\frac{y}{2 x} - 4)

Frequently Asked Questions (FAQ)

What is the solution for y^'=5-2y ?
The solution for y^'=5-2y is y=-(e^{-2t-c_{1}})/2+5/2