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Popular >

y^'=cos^2(y)

Solution

y^{^{'}} = cos^{2} (y)

Solution

y = arctan (t + c_{1}) + πn

Solution steps

y^{'} (t) = cos^{2} (y)

Solve separable ODE:

y = arctan (t + c_{1}) + πn

y = arctan (t + c_{1}) + πn

Popular Examples

tangent of y=(x^2)/(x+1),(2, 4/3)tangent of

y = \frac{x ^{2}}{x + 1}, (2, \frac{4}{3})

(dy)/(dx)+6xy^5=0

\frac{d y}{d x} + 6 x y^{5} = 0

(7x+11y)dx+(11x+5y)dy=0,y(0)=2

(7 x + 11 y) d x + (11 x + 5 y) d y = 0, y (0) = 2

(\partial)/(\partial x)(y/(2sqrt(x))-4)

\frac{\partial}{\partial x} (\frac{y}{2 x} - 4)

derivative of 2x^3-3x+1

\frac{d}{d x} (2 x^{3} - 3 x + 1)

Frequently Asked Questions (FAQ)

What is the solution for y^'=cos^2(y) ?
The solution for y^'=cos^2(y) is y=arctan(t+c_{1})+pin