What is the integral of 3/(x^{2/3)} ?

The integral of 3/(x^{2/3)} is 9x^{1/3}+C

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integral of 3/(x^{2/3)}

\int \frac{3}{x ^{\frac{2}{3}}} d x

9 x^{\frac{1}{3}} + C

Solution steps

\int \frac{3}{x ^{\frac{2}{3}}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{1}{x ^{\frac{2}{3}}} d x

Apply the Power Rule

: 3 x^{\frac{1}{3}}

= 3 \cdot 3 x^{\frac{1}{3}}

Simplify

= 9 x^{\frac{1}{3}}

Add a constant to the solution

= 9 x^{\frac{1}{3}} + C

\frac{d ^{2}}{d x ^{2}} (\frac{6}{7 x ^{5}})

\frac{d y}{d x} + 3 (tan (3 x)) y = - 6 cos (3 x)

\frac{d}{d x} ((2 x^{3}) (4 x^{2}))

(0, 5), (- 1.5, 1)

x \to (0) lim (x^{x^{2}})