What is the derivative of (2x^3(4x^2)) ?

The derivative of (2x^3(4x^2)) is 40x^4

What is the first derivative of (2x^3(4x^2)) ?

The first derivative of (2x^3(4x^2)) is 40x^4

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\frac{d}{d x} ((2 x^{3}) (4 x^{2}))

40 x^{4}

Solution steps

\frac{d}{d x} ((2 x^{3}) (4 x^{2}))

Simplify

(2 x^{3}) (4 x^{2}) : 8 x^{5}

= \frac{d}{d x} (8 x^{5})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (x^{5})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 \cdot 5 x^{5 - 1}

Simplify

= 40 x^{4}

(0, 5), (- 1.5, 1)

x \to (0) lim (x^{x^{2}})

2 t \frac{d y}{d t} - 4 y = t

n = 1 \sum \infty \frac{1}{4 ^{n}}

(t^{2} - 3 t + 2) sin (3 t)

What is the derivative of (2x^3(4x^2)) ?
The derivative of (2x^3(4x^2)) is 40x^4
What is the first derivative of (2x^3(4x^2)) ?
The first derivative of (2x^3(4x^2)) is 40x^4