What is the solution for (dy)/(dx)=((2x(y-1)))/(x^2+3) ?

The solution for (dy)/(dx)=((2x(y-1)))/(x^2+3) is y=e^{c_{1}}x^2+3e^{c_{1}}+1

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(dy)/(dx)=((2x(y-1)))/(x^2+3)

\frac{d y}{d x} = \frac{( 2 x ( y - 1 ) )}{x ^{2} + 3}

y = e^{c_{1}} x^{2} + 3 e^{c_{1}} + 1

Solution steps

\frac{d y}{d x} = \frac{( 2 x ( y - 1 ) )}{x ^{2} + 3}

Solve separable ODE:

y = e^{c_{1}} x^{2} + 3 e^{c_{1}} + 1

y = e^{c_{1}} x^{2} + 3 e^{c_{1}} + 1

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What is the solution for (dy)/(dx)=((2x(y-1)))/(x^2+3) ?
The solution for (dy)/(dx)=((2x(y-1)))/(x^2+3) is y=e^{c_{1}}x^2+3e^{c_{1}}+1