What is the integral of (x^3-6x+5)/x ?

The integral of (x^3-6x+5)/x is (x^3)/3-6x+5ln|x|+C

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integral of (x^3-6x+5)/x

\int \frac{x ^{3} - 6 x + 5}{x} d x

\frac{x ^{3}}{3} - 6 x + 5 ln ∣ x ∣ + C

Solution steps

\int \frac{x ^{3} - 6 x + 5}{x} d x

Expand

\frac{x ^{3} - 6 x + 5}{x} : x^{2} - 6 + \frac{5}{x}

= \int x^{2} - 6 + \frac{5}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int 6 d x + \int \frac{5}{x} d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 6 d x = 6 x

\int \frac{5}{x} d x = 5 ln ∣ x ∣

= \frac{x ^{3}}{3} - 6 x + 5 ln ∣ x ∣

Add a constant to the solution

= \frac{x ^{3}}{3} - 6 x + 5 ln ∣ x ∣ + C

y^{^{''}} - y = 0, y (0) = 2, y^{^{'}} (0) = - 2

\frac{\partial}{\partial x} (x x^{2} + y^{2} + z^{2})

\frac{d}{d x} (\frac{2}{4 - cos ( 2 x )})

\int \frac{1}{t ln ( t ^{2} )} d t

\int \frac{x ^{3} + 5}{5 x + 3} d x

What is the integral of (x^3-6x+5)/x ?
The integral of (x^3-6x+5)/x is (x^3)/3-6x+5ln|x|+C