What is the derivative of x^4+1 ?

The derivative of x^4+1 is 4x^3

What is the first derivative of x^4+1 ?

The first derivative of x^4+1 is 4x^3

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derivative of

x^{4} + 1

4 x^{3}

Solution steps

\frac{d}{d x} (x^{4} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (1) = 0

= 4 x^{3} + 0

Simplify

= 4 x^{3}

\int \frac{1}{x ^{\frac{1}{3}}} d x

\frac{d}{d x} (ln (\frac{5}{x}))

y^{^{''}} + 2 y^{^{'}} - 3 y = 2 x - 17

\frac{1}{cos ( x )}

\frac{d}{d x} (2 x - sin (x))