What is the integral of 1/(x^{1/3)} ?

The integral of 1/(x^{1/3)} is 3/2 x^{2/3}+C

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integral of 1/(x^{1/3)}

\int \frac{1}{x ^{\frac{1}{3}}} d x

\frac{3}{2} x^{\frac{2}{3}} + C

Solution steps

\int \frac{1}{x ^{\frac{1}{3}}} d x

Apply the Power Rule

: \frac{3}{2} x^{\frac{2}{3}}

= \frac{3}{2} x^{\frac{2}{3}}

Add a constant to the solution

= \frac{3}{2} x^{\frac{2}{3}} + C

\frac{d}{d x} (ln (\frac{5}{x}))

y^{^{''}} + 2 y^{^{'}} - 3 y = 2 x - 17

\frac{1}{cos ( x )}

\frac{d}{d x} (2 x - sin (x))

\int_{0}^{2} 4 x^{3} d x

What is the integral of 1/(x^{1/3)} ?
The integral of 1/(x^{1/3)} is 3/2 x^{2/3}+C