What is the integral from 0 to 2 of 4x^3 ?

The integral from 0 to 2 of 4x^3 is 16

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integral from 0 to 2 of 4x^3

\int_{0}^{2} 4 x^{3} d x

16

Solution steps

\int_{0}^{2} 4 x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{0}^{2} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{2}

= 4 [\frac{x ^{4}}{4}]_{0}^{2}

Compute the boundaries:

4

= 4 \cdot 4

Simplify

= 16

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What is the integral from 0 to 2 of 4x^3 ?
The integral from 0 to 2 of 4x^3 is 16