What is the derivative of 2x^3+3x^2-12x ?

The derivative of 2x^3+3x^2-12x is 6x^2+6x-12

What is the first derivative of 2x^3+3x^2-12x ?

The first derivative of 2x^3+3x^2-12x is 6x^2+6x-12

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\frac{d}{d x} (2 x^{3} + 3 x^{2} - 12 x)

6 x^{2} + 6 x - 12

Solution steps

\frac{d}{d x} (2 x^{3} + 3 x^{2} - 12 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) + \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (12 x)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (12 x) = 12

= 6 x^{2} + 6 x - 12

5 x^{2} - 6 x + 1

f (x) = 9 x sin (x)

f (x) = e^{- 5 x}, at x = 0

\frac{d}{d s} (\frac{s ^{2} - 8 s + 15}{s ^{2} + 3 s + 2})

2 y y^{^{'}} + 4 = y^{2} + 4 x

What is the derivative of 2x^3+3x^2-12x ?
The derivative of 2x^3+3x^2-12x is 6x^2+6x-12
What is the first derivative of 2x^3+3x^2-12x ?
The first derivative of 2x^3+3x^2-12x is 6x^2+6x-12