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Popular >

y^'-1/x y=-(y^2)/x

Solution

y^{^{'}} - \frac{1}{x} y = - \frac{y ^{2}}{x}

Solution

y = \frac{x}{x - c _{1}}

Solution steps

y^{'} (x) - \frac{1}{x} y = - \frac{y ^{2}}{x}

Solve separable ODE:

y = \frac{x}{x - c _{1}}

y = \frac{x}{x - c _{1}}

Popular Examples

integral of 10m^{-2.3}+5m^{3.6}

\int 10 m^{- 2.3} + 5 m^{3.6} d m

integral of 1/(u^2-1)

\int \frac{1}{u ^{2} - 1} d u

derivative of sqrt(x)*5x^2 derivative of

x \cdot 5 x^{2}

integral of 1/(1+cos^2(θ))

\int \frac{1}{1 + cos ^{2} ( θ )} d θ

derivative of arccos(sin(x^2+9x))

\frac{d}{d x} (arccos (sin (x^{2} + 9 x)))

Frequently Asked Questions (FAQ)

What is the solution for y^'-1/x y=-(y^2)/x ?
The solution for y^'-1/x y=-(y^2)/x is y= x/(x-c_{1)}