What is (\partial)/(\partial x)(sin(pi(3x-4y))) ?

The answer to (\partial)/(\partial x)(sin(pi(3x-4y))) is cos(pi(3x-4y))*3pi

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(\partial)/(\partial x)(sin(pi(3x-4y)))

\frac{\partial}{\partial x} (sin (π (3 x - 4 y)))

cos (π (3 x - 4 y)) \cdot 3 π

Solution steps

\frac{\partial}{\partial x} (sin (π (3 x - 4 y)))

Treat

y

as a constant

Apply the chain rule:

cos (π (3 x - 4 y)) \frac{\partial}{\partial x} (π (3 x - 4 y))

= cos (π (3 x - 4 y)) \frac{\partial}{\partial x} (π (3 x - 4 y))

\frac{\partial}{\partial x} (π (3 x - 4 y)) = 3 π

= cos (π (3 x - 4 y)) \cdot 3 π

\frac{d}{d x} (\frac{5}{( 6 x + 5 ) ^{2}})

\int_{0}^{8} \frac{1}{64 - t ^{2}} d t

f (x) = - \frac{1}{x ^{2}}

y = - x^{2} + 1, (0, 1)

\frac{7 x + 1}{2 x - 3}

What is (\partial)/(\partial x)(sin(pi(3x-4y))) ?
The answer to (\partial)/(\partial x)(sin(pi(3x-4y))) is cos(pi(3x-4y))*3pi