What is the solution for (dy)/(dt)=y(8-y),y(0)=9 ?

The solution for (dy)/(dt)=y(8-y),y(0)=9 is y=(72e^{8t})/(-1+9e^{8t)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dt)=y(8-y),y(0)=9

\frac{d y}{d t} = y (8 - y), y (0) = 9

y = \frac{72 e ^{8 t}}{- 1 + 9 e ^{8 t}}

Solution steps

\frac{d y}{d t} = y (8 - y)

Solve Bernoulli ODE:

y = \frac{72 e ^{8 t}}{- 1 + 9 e ^{8 t}}

y = \frac{72 e ^{8 t}}{- 1 + 9 e ^{8 t}}

\int sec^{2} (2 x) tan^{2} (2 x) d x

n = 0 \sum \infty \frac{9 ^{n}}{n !}

\frac{d}{d x} (3 x^{2} - 5)

y^{^{'}} = \frac{5 y}{x}

f (x) = 2 x^{2} + x, at x = 0

What is the solution for (dy)/(dt)=y(8-y),y(0)=9 ?
The solution for (dy)/(dt)=y(8-y),y(0)=9 is y=(72e^{8t})/(-1+9e^{8t)}