What is the tangent of (13)/x ?

The tangent of (13)/x is y=-(13)/(a_{0)^2}x+(26)/(a_{0)}

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tangent of (13)/x

tangent of

\frac{13}{x}

y = - \frac{13}{a _{0}^{2}} x + \frac{26}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{13}{a _{0}})

Find the slope of

y = \frac{13}{x} : \frac{d y}{d x} = - \frac{13}{x ^{2}}

Compute the slope of

y = \frac{13}{x}

x = a_{0} : m = - \frac{13}{a _{0}^{2}}

Find the line with slope m=

- \frac{13}{a _{0}^{2}}

and passing through

(a_{0}, \frac{13}{a _{0}}) : y = - \frac{13}{a _{0}^{2}} x + \frac{26}{a _{0}}

y = - \frac{13}{a _{0}^{2}} x + \frac{26}{a _{0}}

f (x) = 2 x^{4} - 6 x^{2}, at x = 1

x y 2 = 2 + x y

\int_{0}^{1} 2 x^{2} d x

\int \frac{1}{x ^{2} - 2 x - 8} d x

f (x) = x^{2} - 20 x, g (x) = 0

What is the tangent of (13)/x ?
The tangent of (13)/x is y=-(13)/(a_{0)^2}x+(26)/(a_{0)}