What is the first (ln(1-7x))^' ?

The first (ln(1-7x))^' is -7/(1-7x)

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(ln(1-7x))^'

(ln (1 - 7 x))^{^{'}}

- \frac{7}{1 - 7 x}

Solution steps

(ln (1 - 7 x))^{'}

Apply the chain rule:

\frac{1}{1 - 7 x} (1 - 7 x)^{'}

= \frac{1}{1 - 7 x} (1 - 7 x)^{'}

(1 - 7 x)^{'} = - 7

= \frac{1}{1 - 7 x} (- 7)

Simplify

\frac{1}{1 - 7 x} (- 7) : - \frac{7}{1 - 7 x}

= - \frac{7}{1 - 7 x}

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