What is the integral of cos(x)sin^6(x) ?

The integral of cos(x)sin^6(x) is (sin^7(x))/7+C

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integral of cos(x)sin^6(x)

\int cos (x) sin^{6} (x) d x

\frac{sin ^{7} ( x )}{7} + C

Solution steps

\int cos (x) sin^{6} (x) d x

Apply u-substitution

: \int u^{6} d u

= \int u^{6} d u

Apply the Power Rule

: \frac{u ^{7}}{7}

= \frac{u ^{7}}{7}

Substitute back

u = sin (x)

= \frac{sin ^{7} ( x )}{7}

Add a constant to the solution

= \frac{sin ^{7} ( x )}{7} + C

f (x) = 7 tan (x^{4})

2 y^{^{'}} + 4 y = 1

\int_{0}^{3.5} 70 x d x

\frac{d}{d x} (ln ∣ sin (x) ∣)

70 π t + 35 cos (\frac{- 2 π t - π}{2})

What is the integral of cos(x)sin^6(x) ?
The integral of cos(x)sin^6(x) is (sin^7(x))/7+C