What is the slope of y= 3/(x+1),(2,1) ?

The slope of y= 3/(x+1),(2,1) is -1/3

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slope of y= 3/(x+1),(2,1)

slope

y = \frac{3}{x + 1}, (2, 1)

- \frac{1}{3}

Solution steps

y = \frac{3}{x + 1}

In order to find the slope of the function, take the derivative of

\frac{3}{x + 1}

\frac{d}{d x} (\frac{3}{x + 1}) = - \frac{3}{( x + 1 ) ^{2}}

- \frac{3}{( x + 1 ) ^{2}}

Find the value of

- \frac{3}{( x + 1 ) ^{2}}

for

x = 2 : - \frac{1}{3}

- \frac{1}{3}

\frac{x y d y}{d x} = 2 x^{2} + 2 y^{2}

\int 5 e^{x + 5} d x

2 t \cdot \frac{d y}{d t} + y = t

\int_{1}^{3} \frac{2}{x ^{2} + 2 x + 1} d x

f (x) = x^{2} + 5, at x = - 2