What is the integral of (1/(x^2+1)) ?

The integral of (1/(x^2+1)) is arctan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (1/(x^2+1))

\int (\frac{1}{x ^{2} + 1}) d x

arctan (x) + C

Solution steps

\int \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= arctan (x)

Add a constant to the solution

= arctan (x) + C

\int 4 x^{3} + e^{x} - 1 d x

x \to 2 lim (\frac{x + 2}{x ^{3} + 8})

\int (\frac{2}{1 + x ^{2}}) d x

\frac{x ^{5} - 5}{x + 1}

What is the integral of (1/(x^2+1)) ?
The integral of (1/(x^2+1)) is arctan(x)+C