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Frequently Asked Questions (FAQ)
What is the solution for y^'+(3x)/(x^2+4)y= x/(x^2+4),y(0)=1 ?
- The solution for y^'+(3x)/(x^2+4)y= x/(x^2+4),y(0)=1 is y= 1/3+(16)/(3(x^2+4)^{3/2)}