What is the integral of (7/(x^2+1)) ?

The integral of (7/(x^2+1)) is 7arctan(x)+C

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integral of (7/(x^2+1))

\int (\frac{7}{x ^{2} + 1}) d x

7 arctan (x) + C

Solution steps

\int \frac{7}{x ^{2} + 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= 7 arctan (x)

Add a constant to the solution

= 7 arctan (x) + C

\frac{d}{d x} (csc^{3} (x^{2}))

\frac{d}{d x} ((1 + x^{3})^{2020})

\frac{d}{d x} (4 e^{- x^{2}})

(8, 8), (4, 6)

e^{2 x} + 2 e^{2 x} x

What is the integral of (7/(x^2+1)) ?
The integral of (7/(x^2+1)) is 7arctan(x)+C