What is the derivative of sin(t^2) ?

The derivative of sin(t^2) is cos(t^2)*2t

What is the first derivative of sin(t^2) ?

The first derivative of sin(t^2) is cos(t^2)*2t

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derivative of

sin (t^{2})

cos (t^{2}) \cdot 2 t

Solution steps

\frac{d}{d t} (sin (t^{2}))

Apply the chain rule:

cos (t^{2}) \frac{d}{d t} (t^{2})

= cos (t^{2}) \frac{d}{d t} (t^{2})

\frac{d}{d t} (t^{2}) = 2 t

= cos (t^{2}) \cdot 2 t

\int t e^{- i 2 π f t} d t

\int_{0}^{π} cos (3 x) d x

y^{^{''}} + 4 y^{^{'}} + 13 y = 0, y (0) = 7, y^{^{'}} (0) = 7

f (x) = (3 x - 4)

\frac{d}{d x} (50 x)

What is the derivative of sin(t^2) ?
The derivative of sin(t^2) is cos(t^2)*2t
What is the first derivative of sin(t^2) ?
The first derivative of sin(t^2) is cos(t^2)*2t