What is the derivative of-(14/(x^3)) ?

The derivative of-(14/(x^3)) is (42)/(x^4)

What is the first derivative of-(14/(x^3)) ?

The first derivative of-(14/(x^3)) is (42)/(x^4)

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\frac{d}{d x} (- \frac{14}{x ^{3}})

\frac{42}{x ^{4}}

Solution steps

\frac{d}{d x} (- \frac{14}{x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 14 \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 14 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 14 (- 3 x^{- 3 - 1})

Simplify

- 14 (- 3 x^{- 3 - 1}) : \frac{42}{x ^{4}}

= \frac{42}{x ^{4}}

(11 + x^{2}) y^{^{'}} - 2 x y = 0

\int \frac{1}{8 x ^{2} - 16 x + 64} d x

\frac{\partial}{\partial t} (s e^{t})

\frac{\partial}{\partial t} (s sin (t))

x \to - 2 lim (\frac{5}{x + 2})

What is the derivative of-(14/(x^3)) ?
The derivative of-(14/(x^3)) is (42)/(x^4)
What is the first derivative of-(14/(x^3)) ?
The first derivative of-(14/(x^3)) is (42)/(x^4)