What is (\partial)/(\partial y)(-8e^xln(y)) ?

The answer to (\partial)/(\partial y)(-8e^xln(y)) is -(8e^x)/y

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(\partial)/(\partial y)(-8e^xln(y))

\frac{\partial}{\partial y} (- 8 e^{x} ln (y))

- \frac{8 e ^{x}}{y}

Solution steps

\frac{\partial}{\partial y} (- 8 e^{x} ln (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 e^{x} \frac{\partial}{\partial y} (ln (y))

Apply the common derivative:

\frac{\partial}{\partial y} (ln (y)) = \frac{1}{y}

= - 8 e^{x} \frac{1}{y}

Simplify

- 8 e^{x} \frac{1}{y} : - \frac{8 e ^{x}}{y}

= - \frac{8 e ^{x}}{y}

2 x cos (x^{2})

x + 3 3 x^{2} - 2 x + 5

- y^{2} - y e^{t} + (y + e^{t}) (\frac{d y}{d t}) = 0

\int \frac{1}{( 6 x ^{2} + 9 ) ^{4}} x d x

x \to \infty lim (1 + \frac{6}{x})

What is (\partial)/(\partial y)(-8e^xln(y)) ?
The answer to (\partial)/(\partial y)(-8e^xln(y)) is -(8e^x)/y