What is the derivative of f(x)=2sqrt(x)+(10)/(x^7) ?

The derivative of f(x)=2sqrt(x)+(10)/(x^7) is (x^{15/2}-70)/(x^{15/2)sqrt(x)}

What is the first derivative of f(x)=2sqrt(x)+(10)/(x^7) ?

The first derivative of f(x)=2sqrt(x)+(10)/(x^7) is (x^{15/2}-70)/(x^{15/2)sqrt(x)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = 2 x + \frac{10}{x ^{7}}

\frac{x ^{\frac{15}{2}} - 70}{x ^{\frac{15}{2}} x}

Solution steps

\frac{d}{d x} (2 x + \frac{10}{x ^{7}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (\frac{10}{x ^{7}})

\frac{d}{d x} (2 x) = \frac{1}{x}

\frac{d}{d x} (\frac{10}{x ^{7}}) = - \frac{70}{x ^{8}}

= \frac{1}{x} - \frac{70}{x ^{8}}

Simplify

\frac{1}{x} - \frac{70}{x ^{8}} : \frac{x ^{\frac{15}{2}} - 70}{x ^{\frac{15}{2}} x}

= \frac{x ^{\frac{15}{2}} - 70}{x ^{\frac{15}{2}} x}

(1 - x y) y^{^{'}} = y^{2}

y = 0 \sum \infty 2^{- 2 - y + x}

\frac{\partial}{\partial y} (x 1 + y^{5})

\int t e^{- a t} d t

f (t) = t sin (t) + cos (t)

What is the derivative of f(x)=2sqrt(x)+(10)/(x^7) ?
The derivative of f(x)=2sqrt(x)+(10)/(x^7) is (x^{15/2}-70)/(x^{15/2)sqrt(x)}
What is the first derivative of f(x)=2sqrt(x)+(10)/(x^7) ?
The first derivative of f(x)=2sqrt(x)+(10)/(x^7) is (x^{15/2}-70)/(x^{15/2)sqrt(x)}