What is the derivative of y=sin(2t) ?

The derivative of y=sin(2t) is cos(2t)*2

What is the first derivative of y=sin(2t) ?

The first derivative of y=sin(2t) is cos(2t)*2

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derivative of

y = sin (2 t)

cos (2 t) \cdot 2

Solution steps

\frac{d}{d t} (sin (2 t))

Apply the chain rule:

cos (2 t) \frac{d}{d t} (2 t)

= cos (2 t) \frac{d}{d t} (2 t)

\frac{d}{d t} (2 t) = 2

= cos (2 t) \cdot 2

\int 4 cos^{4} (5 x) d x

f (x) = \frac{e ^{x}}{1 + e ^{x}}

f (x) = \frac{x ^{2} + 2 x - 2}{( x + 1 ) ^{2}}

\frac{d}{d t} (6 cos (t))

\int_{1}^{2} x^{- 2} d x

What is the derivative of y=sin(2t) ?
The derivative of y=sin(2t) is cos(2t)*2
What is the first derivative of y=sin(2t) ?
The first derivative of y=sin(2t) is cos(2t)*2