What is the derivative of sin^4(4x) ?

The derivative of sin^4(4x) is 16sin^3(4x)cos(4x)

What is the first derivative of sin^4(4x) ?

The first derivative of sin^4(4x) is 16sin^3(4x)cos(4x)

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\frac{d}{d x} (sin^{4} (4 x))

16 sin^{3} (4 x) cos (4 x)

Solution steps

\frac{d}{d x} (sin^{4} (4 x))

Apply the chain rule:

4 (sin (4 x))^{3} \frac{d}{d x} (sin (4 x))

= 4 (sin (4 x))^{3} \frac{d}{d x} (sin (4 x))

\frac{d}{d x} (sin (4 x)) = cos (4 x) \cdot 4

= 4 (sin (4 x))^{3} cos (4 x) \cdot 4

Simplify

= 16 sin^{3} (4 x) cos (4 x)

\frac{d x}{d y} = 3 x (5 - x)

(3 t + 6 y + 3) = \frac{d y}{d t}

x

\int 1 - x d x

y = - x^{3}, (- 2, 8)

What is the derivative of sin^4(4x) ?
The derivative of sin^4(4x) is 16sin^3(4x)cos(4x)
What is the first derivative of sin^4(4x) ?
The first derivative of sin^4(4x) is 16sin^3(4x)cos(4x)