What is derivative of x=6.4cos(1.2^2t^2) ?

The answer to derivative of x=6.4cos(1.2^2t^2) is (dt)/(dx)=-1/(18.432tsin(1.44t^2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of x=6.4cos(1.2^2t^2)

derivative of

x = 6.4 cos (1. 2^{2} t^{2})

\frac{d t}{d x} = - \frac{1}{18.432 t sin ( 1.44 t ^{2} )}

Solution steps

x = 6.4 cos (1. 2^{2} t^{2})

Treat

t

t (x)

Differentiate both sides:

1 = - 18.432 sin (1.44 t^{2}) t \frac{d t}{d x}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = - \frac{1}{18.432 t sin ( 1.44 t ^{2} )}

\frac{d t}{d x} = - \frac{1}{18.432 t sin ( 1.44 t ^{2} )}

\int sin (4 x) sin (3 x) d x

x \to π lim (ln (tan (x)))

x \to - \infty lim (e^{- x} + x - 1)

\frac{d}{d x} (13 arctan (x))

(3 x^{4} + 4)^{2}

What is derivative of x=6.4cos(1.2^2t^2) ?
The answer to derivative of x=6.4cos(1.2^2t^2) is (dt)/(dx)=-1/(18.432tsin(1.44t^2))