What is the tangent of 6/(x^2+4) ?

The tangent of 6/(x^2+4) is y=-(12a_{0})/((a_{0)^2+4)^2}x+(18a_{0}^2+24)/((a_{0)^2+4)^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 6/(x^2+4)

tangent of

\frac{6}{x ^{2} + 4}

y = - \frac{12 a _{0}}{( a _{0}^{2} + 4 ) ^{2}} x + \frac{18 a _{0}^{2} + 24}{( a _{0}^{2} + 4 ) ^{2}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{6}{a _{0}^{2} + 4})

Find the slope of

y = \frac{6}{x ^{2} + 4} : \frac{d y}{d x} = - \frac{12 x}{( x ^{2} + 4 ) ^{2}}

Compute the slope of

y = \frac{6}{x ^{2} + 4}

x = a_{0} : m = - \frac{12 a _{0}}{( a _{0}^{2} + 4 ) ^{2}}

Find the line with slope m=

- \frac{12 a _{0}}{( a _{0}^{2} + 4 ) ^{2}}

and passing through

(a_{0}, \frac{6}{a _{0}^{2} + 4}) : y = - \frac{12 a _{0}}{( a _{0}^{2} + 4 ) ^{2}} x + \frac{18 a _{0}^{2} + 24}{( a _{0}^{2} + 4 ) ^{2}}

y = - \frac{12 a _{0}}{( a _{0}^{2} + 4 ) ^{2}} x + \frac{18 a _{0}^{2} + 24}{( a _{0}^{2} + 4 ) ^{2}}

\frac{\partial}{\partial x} (4 π^{2} \frac{y}{x ^{2}})

arctan (2 x)

x \to 0 lim (\frac{2 x}{0})

e^{x}, x, 0, 2

x \to - 4 lim (- \frac{8}{x ^{2} + 8 x + 16})

What is the tangent of 6/(x^2+4) ?
The tangent of 6/(x^2+4) is y=-(12a_{0})/((a_{0)^2+4)^2}x+(18a_{0}^2+24)/((a_{0)^2+4)^2}