What is the limit as x approaches-4 of-8/(x^2+8x+16) ?

The limit as x approaches-4 of-8/(x^2+8x+16) is -infinity

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limit as x approaches-4 of-8/(x^2+8x+16)

x \to - 4 lim (- \frac{8}{x ^{2} + 8 x + 16})

- \infty

Solution steps

x \to - 4 lim (- \frac{8}{x ^{2} + 8 x + 16})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to - 4 - lim (- \frac{8}{x ^{2} + 8 x + 16}) = - \infty

x \to - 4 + lim (- \frac{8}{x ^{2} + 8 x + 16}) = - \infty

= - \infty

x \to 0 lim ((1 - 5 x)^{\frac{4}{x}})

\int \frac{2}{x ^{2} 9 + x ^{2}} d x

x \to - 2 lim (\frac{x - 1}{3 x + 6})

(y^{4} - x^{2}) \cdot \frac{d y}{d x} = - x y

What is the limit as x approaches-4 of-8/(x^2+8x+16) ?
The limit as x approaches-4 of-8/(x^2+8x+16) is -infinity