What is the solution for (y^4-x^2)*(dy)/(dx)=-xy ?

The solution for (y^4-x^2)*(dy)/(dx)=-xy is

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(y^4-x^2)*(dy)/(dx)=-xy

(y^{4} - x^{2}) \cdot \frac{d y}{d x} = - x y

y = c_{1} + - x^{2} + c_{1}^{2}, y = - c_{1} + - x^{2} + c_{1}^{2}, y = c_{1} - - x^{2} + c_{1}^{2}, y = - c_{1} - - x^{2} + c_{1}^{2}

Solution steps

(y^{4} - x^{2}) \cdot \frac{d y}{d x} = - x y

Solve exact ODE:

y = c_{1} + - x^{2} + c_{1}^{2}, y = - c_{1} + - x^{2} + c_{1}^{2}, y = c_{1} - - x^{2} + c_{1}^{2}, y = - c_{1} - - x^{2} + c_{1}^{2}

y = c_{1} + - x^{2} + c_{1}^{2}, y = - c_{1} + - x^{2} + c_{1}^{2}, y = c_{1} - - x^{2} + c_{1}^{2}, y = - c_{1} - - x^{2} + c_{1}^{2}

\int (x - 1)^{5} d x

e^{- t} cos (2 t)

x \to 0 + lim ((\frac{1}{5})^{\frac{1}{x}})

\frac{\partial}{\partial x} (x^{\frac{1}{2}} y^{\frac{1}{2}} z)

\int_{0}^{6} 1 + x d x

What is the solution for (y^4-x^2)*(dy)/(dx)=-xy ?
The solution for (y^4-x^2)*(dy)/(dx)=-xy is