What is (\partial)/(\partial y)(3x^2+2xy^3) ?

The answer to (\partial)/(\partial y)(3x^2+2xy^3) is 6xy^2

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(\partial)/(\partial y)(3x^2+2xy^3)

\frac{\partial}{\partial y} (3 x^{2} + 2 x y^{3})

6 x y^{2}

Solution steps

\frac{\partial}{\partial y} (3 x^{2} + 2 x y^{3})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2}) + \frac{\partial}{\partial y} (2 x y^{3})

\frac{\partial}{\partial y} (3 x^{2}) = 0

\frac{\partial}{\partial y} (2 x y^{3}) = 6 x y^{2}

= 0 + 6 x y^{2}

Simplify

= 6 x y^{2}

n = 1 \sum \infty \frac{x ^{n}}{6 ^{n}}

\int tan (x) y d y

ln (14 - 9 x^{2} + 2 x^{4})

\frac{d}{d x} (\frac{2 x ^{2} + 4 x}{2 + x ^{2}})

\int cos (t) sin (t) d t

What is (\partial)/(\partial y)(3x^2+2xy^3) ?
The answer to (\partial)/(\partial y)(3x^2+2xy^3) is 6xy^2