What is (\partial)/(\partial x)(((x^2))/(y+1)) ?

The answer to (\partial)/(\partial x)(((x^2))/(y+1)) is (2x)/(y+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(((x^2))/(y+1))

\frac{\partial}{\partial x} (\frac{( x ^{2} )}{y + 1})

\frac{2 x}{y + 1}

Solution steps

\frac{\partial}{\partial x} (\frac{( x ^{2} )}{y + 1})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{y + 1} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{y + 1} \cdot 2 x^{2 - 1}

Simplify

\frac{1}{y + 1} \cdot 2 x^{2 - 1} : \frac{2 x}{y + 1}

= \frac{2 x}{y + 1}

\int \frac{y}{( y ^{2} - 1 ) ^{\frac{3}{2}}} d y

(ln (x + 1))^{^{'}}

x^{2} + 1, 0, 1

x \to \infty lim (1.0 1^{x})

(x^{2} - x + 1) y^{^{''}} - (x^{2} + x) y^{^{'}} + (x + 1) y = 0

What is (\partial)/(\partial x)(((x^2))/(y+1)) ?
The answer to (\partial)/(\partial x)(((x^2))/(y+1)) is (2x)/(y+1)