What is the limit as x approaches infinity of 1.01^x ?

The limit as x approaches infinity of 1.01^x is infinity

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limit as x approaches infinity of 1.01^x

x \to \infty lim (1.0 1^{x})

\infty

Solution steps

x \to \infty lim (1.0 1^{x})

Apply the common limit:

x \to \infty lim (a^{x}) = \infty, a > 1

= \infty

(x^{2} - x + 1) y^{^{''}} - (x^{2} + x) y^{^{'}} + (x + 1) y = 0

y = 2187 x, y = 81 x^{2}

6 sin (x)

\frac{\partial}{\partial x} (x^{3} y e^{x y})

\frac{\partial}{\partial x} (x^{2} - x + 2 y^{2} + yz - 10)

What is the limit as x approaches infinity of 1.01^x ?
The limit as x approaches infinity of 1.01^x is infinity