What is the tangent of f(x)=12(x-(1/x)^4),\at x=2 ?

The tangent of f(x)=12(x-(1/x)^4),\at x=2 is y= 27/2 x-15/4

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tangent of f(x)=12(x-(1/x)^4),\at x=2

tangent of

f (x) = 12 (x - (\frac{1}{x})^{4}), at x = 2

y = \frac{27}{2} x - \frac{15}{4}

Solution steps

Find the tangent point:

(2, \frac{93}{4})

Find the slope of

f (x) = 12 (x - (\frac{1}{x})^{4}) : \frac{df ( x )}{d x} = 12 (1 + \frac{4}{x ^{5}})

Compute the slope of

f (x) = 12 (x - (\frac{1}{x})^{4})

x = 2 : m = \frac{27}{2}

Find the line with slope m=

\frac{27}{2}

and passing through

(2, \frac{93}{4}) : y = \frac{27}{2} x - \frac{15}{4}

y = \frac{27}{2} x - \frac{15}{4}

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What is the tangent of f(x)=12(x-(1/x)^4),\at x=2 ?
The tangent of f(x)=12(x-(1/x)^4),\at x=2 is y= 27/2 x-15/4