What is derivative of f(x)=x^2-4xy+y^2=4 ?

The answer to derivative of f(x)=x^2-4xy+y^2=4 is (df)/(dx)=0

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derivative of f(x)=x^2-4xy+y^2=4

derivative of

f (x) = x^{2} - 4 x y + y^{2} = 4

\frac{df}{d x} = 0

Solution steps

f = x^{2} - 4 x f + f^{2} = 4

Treat

f

f (x)

Differentiate both sides:

\frac{df}{d x} = 0

Isolate

\frac{df}{d x} : \frac{df}{d x} = 0

\frac{df}{d x} = 0

\int_{1}^{3} 17 x^{3} ln (x) d x

\int cos^{- 2} (x) d x

\int \frac{y - 3}{y - 2} d y

\int e^{x + 4} d x

y^{^{'}} = (x + y)^{2} - 1

What is derivative of f(x)=x^2-4xy+y^2=4 ?
The answer to derivative of f(x)=x^2-4xy+y^2=4 is (df)/(dx)=0