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Popular >

y^'=(x+y)^2-1

Solution

y^{^{'}} = (x + y)^{2} - 1

Solution

y = - \frac{1}{x + c _{1}} - x

Solution steps

y^{'} (x) = (x + y)^{2} - 1

Solve using substitution:

y = - \frac{1}{x + c _{1}} - x

y = - \frac{1}{x + c _{1}} - x

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Frequently Asked Questions (FAQ)

What is the solution for y^'=(x+y)^2-1 ?
The solution for y^'=(x+y)^2-1 is y=-1/(x+c_{1)}-x