What is (\partial)/(\partial x)(3x^{2y}) ?

The answer to (\partial)/(\partial x)(3x^{2y}) is 6yx^{2y-1}

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(\partial)/(\partial x)(3x^{2y})

\frac{\partial}{\partial x} (3 x^{2 y})

6 y x^{2 y - 1}

Solution steps

\frac{\partial}{\partial x} (3 x^{2 y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{\partial}{\partial x} (x^{2 y})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 \cdot 2 y x^{2 y - 1}

Simplify

= 6 y x^{2 y - 1}

s (t) = - 9.8 t^{2} + 2 t + 1

y = (2 x + 3)^{5} + 10 x (2 x + 3)^{4}

\int e x^{2} + π d x

f (x) = arcsin^{2} (x)

x \to 0 + lim (6 sin (x) ln (x))

What is (\partial)/(\partial x)(3x^{2y}) ?
The answer to (\partial)/(\partial x)(3x^{2y}) is 6yx^{2y-1}