What is the derivative of s(t)=-9.8t^2+2t+1 ?

The derivative of s(t)=-9.8t^2+2t+1 is -19.6t+2

What is the first derivative of s(t)=-9.8t^2+2t+1 ?

The first derivative of s(t)=-9.8t^2+2t+1 is -19.6t+2

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derivative of

s (t) = - 9.8 t^{2} + 2 t + 1

- 19.6 t + 2

Solution steps

\frac{d}{d t} (- 9.8 t^{2} + 2 t + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (9.8 t^{2}) + \frac{d}{d t} (2 t) + \frac{d}{d t} (1)

\frac{d}{d t} (9.8 t^{2}) = 19.6 t

\frac{d}{d t} (2 t) = 2

\frac{d}{d t} (1) = 0

= - 19.6 t + 2 + 0

Simplify

= - 19.6 t + 2

y = (2 x + 3)^{5} + 10 x (2 x + 3)^{4}

\int e x^{2} + π d x

f (x) = arcsin^{2} (x)

x \to 0 + lim (6 sin (x) ln (x))

\int \frac{x ^{2}}{10} d x

What is the derivative of s(t)=-9.8t^2+2t+1 ?
The derivative of s(t)=-9.8t^2+2t+1 is -19.6t+2
What is the first derivative of s(t)=-9.8t^2+2t+1 ?
The first derivative of s(t)=-9.8t^2+2t+1 is -19.6t+2