What is the integral of (x^2)/(10) ?

The integral of (x^2)/(10) is (x^3)/(30)+C

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integral of (x^2)/(10)

\int \frac{x ^{2}}{10} d x

\frac{x ^{3}}{30} + C

Solution steps

\int \frac{x ^{2}}{10} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{10} \cdot \int x^{2} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= \frac{1}{10} \cdot \frac{x ^{3}}{3}

Simplify

\frac{1}{10} \cdot \frac{x ^{3}}{3} : \frac{x ^{3}}{30}

= \frac{x ^{3}}{30}

Add a constant to the solution

= \frac{x ^{3}}{30} + C

\int \frac{x ^{8} + 1}{x ^{9} + 9 x} d x

4^{t}

\frac{d}{d x} (\frac{4}{x + 6})

f (x) = - 4 tan (x) - 1, at x = - \frac{π}{4}