What is the solution for (dy)/(dx)=((y-1))/((x+3)) ?

The solution for (dy)/(dx)=((y-1))/((x+3)) is y=e^{c_{1}}x+3e^{c_{1}}+1

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(dy)/(dx)=((y-1))/((x+3))

\frac{d y}{d x} = \frac{( y - 1 )}{( x + 3 )}

y = e^{c_{1}} x + 3 e^{c_{1}} + 1

Solution steps

\frac{d y}{d x} = \frac{( y - 1 )}{( x + 3 )}

Solve separable ODE:

y = e^{c_{1}} x + 3 e^{c_{1}} + 1

y = e^{c_{1}} x + 3 e^{c_{1}} + 1

x \to - 2 lim (\frac{x ^{3} - 8}{x + 2})

x \to 2 lim (x + 5)

f (x) = (x^{2} + 3)^{\frac{1}{2}}, at x = 1

\int (1 - \frac{x}{4})^{2} d x

y^{^{'}} = - 2 x y^{3}

What is the solution for (dy)/(dx)=((y-1))/((x+3)) ?
The solution for (dy)/(dx)=((y-1))/((x+3)) is y=e^{c_{1}}x+3e^{c_{1}}+1