What is the derivative of (3x^2-4x^2) ?

The derivative of (3x^2-4x^2) is 2(3x^2-4x)(6x-4)

What is the first derivative of (3x^2-4x^2) ?

The first derivative of (3x^2-4x^2) is 2(3x^2-4x)(6x-4)

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\frac{d}{d x} ((3 x^{2} - 4 x)^{2})

2 (3 x^{2} - 4 x) (6 x - 4)

Solution steps

\frac{d}{d x} ((3 x^{2} - 4 x)^{2})

Apply the chain rule:

2 (3 x^{2} - 4 x) \frac{d}{d x} (3 x^{2} - 4 x)

= 2 (3 x^{2} - 4 x) \frac{d}{d x} (3 x^{2} - 4 x)

\frac{d}{d x} (3 x^{2} - 4 x) = 6 x - 4

= 2 (3 x^{2} - 4 x) (6 x - 4)

x^{2} + 3 x + 1

f (t) = 7 t + 3

\int \frac{1}{x 1 - x ^{2}} d x

f (x) = \frac{1 - 3 x}{6 + x}

What is the derivative of (3x^2-4x^2) ?
The derivative of (3x^2-4x^2) is 2(3x^2-4x)(6x-4)
What is the first derivative of (3x^2-4x^2) ?
The first derivative of (3x^2-4x^2) is 2(3x^2-4x)(6x-4)